Calcium Homeostasis — MFDS Part 1 MCQ
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Correct answer: B — Increasing osteoprotegerin expression by osteoblast-lineage cells, thereby suppressing osteoclastogenesis
Explanation lettering: E = shown as A · A = shown as B · D = shown as C · C = shown as D · B = shown as E
A is correct. Osteoprotegerin is a decoy receptor for RANKL; increasing it suppresses osteoclast differentiation and bone resorption, so this would oppose the calcium-raising response. Sustained PTH instead increases the RANKL-to-osteoprotegerin ratio in osteoblast-lineage cells, indirectly promoting osteoclastogenesis and calcium release from bone (D). PTH also increases distal tubular calcium reabsorption (B), activates renal 1α-hydroxylase to increase calcitriol and intestinal calcium absorption (C), and decreases proximal tubular phosphate reabsorption (E). The resulting phosphaturia helps maintain ionised calcium by reducing phosphate available for calcium binding. Importantly, PTH primarily promotes osteoclast activity indirectly through osteoblasts and osteocytes rather than simply acting directly on osteoclasts.
Reference: Cartwright C et al. Hungry Bone Syndrome After Parathyroidectomy for Secondary Hyperparathyroidism: Pathogenesis and Contemporary Clinical Considerations, 2025. https://pubmed.ncbi.nlm.nih.gov/36894509/